x(2x-4)=(2x+3)(x-7)

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Solution for x(2x-4)=(2x+3)(x-7) equation: 



x(2x-4)=(2x+3)(x-7)

We move all terms to the left:

x(2x-4)-((2x+3)(x-7))=0

We multiply parentheses

2x^2-4x-((2x+3)(x-7))=0

We multiply parentheses ..

2x^2-((+2x^2-14x+3x-21))-4x=0



We calculate terms in parentheses: -((+2x^2-14x+3x-21)), so:

(+2x^2-14x+3x-21)

We get rid of parentheses

2x^2-14x+3x-21

We add all the numbers together, and all the variables

2x^2-11x-21

Back to the equation:

-(2x^2-11x-21)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-11x-21)=0

We get rid of parentheses

2x^2-2x^2-4x+11x+21=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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