x(2x-4)=(2x+4)(x-6)

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Solution for x(2x-4)=(2x+4)(x-6) equation:



x(2x-4)=(2x+4)(x-6)
We move all terms to the left:
x(2x-4)-((2x+4)(x-6))=0
We multiply parentheses
2x^2-4x-((2x+4)(x-6))=0
We multiply parentheses ..
2x^2-((+2x^2-12x+4x-24))-4x=0
We calculate terms in parentheses: -((+2x^2-12x+4x-24)), so:
(+2x^2-12x+4x-24)
We get rid of parentheses
2x^2-12x+4x-24
We add all the numbers together, and all the variables
2x^2-8x-24
Back to the equation:
-(2x^2-8x-24)
We add all the numbers together, and all the variables
2x^2-4x-(2x^2-8x-24)=0
We get rid of parentheses
2x^2-2x^2-4x+8x+24=0
We add all the numbers together, and all the variables
4x+24=0
We move all terms containing x to the left, all other terms to the right
4x=-24
x=-24/4
x=-6

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