x(2x-4)=(2x+4)(x-6)

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Solution for x(2x-4)=(2x+4)(x-6) equation: 



x(2x-4)=(2x+4)(x-6)

We move all terms to the left:

x(2x-4)-((2x+4)(x-6))=0

We multiply parentheses

2x^2-4x-((2x+4)(x-6))=0

We multiply parentheses ..

2x^2-((+2x^2-12x+4x-24))-4x=0



We calculate terms in parentheses: -((+2x^2-12x+4x-24)), so:

(+2x^2-12x+4x-24)

We get rid of parentheses

2x^2-12x+4x-24

We add all the numbers together, and all the variables

2x^2-8x-24

Back to the equation:

-(2x^2-8x-24)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-8x-24)=0

We get rid of parentheses

2x^2-2x^2-4x+8x+24=0

We add all the numbers together, and all the variables

4x+24=0

We move all terms containing x to the left, all other terms to the right

4x=-24

x=-24/4

x=-6

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