x(2x-4)=(2x+5)(x-3)

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Solution for x(2x-4)=(2x+5)(x-3) equation: 



x(2x-4)=(2x+5)(x-3)

We move all terms to the left:

x(2x-4)-((2x+5)(x-3))=0

We multiply parentheses

2x^2-4x-((2x+5)(x-3))=0

We multiply parentheses ..

2x^2-((+2x^2-6x+5x-15))-4x=0



We calculate terms in parentheses: -((+2x^2-6x+5x-15)), so:

(+2x^2-6x+5x-15)

We get rid of parentheses

2x^2-6x+5x-15

We add all the numbers together, and all the variables

2x^2-1x-15

Back to the equation:

-(2x^2-1x-15)



We add all the numbers together, and all the variables

2x^2-4x-(2x^2-1x-15)=0

We get rid of parentheses

2x^2-2x^2-4x+1x+15=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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