If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(2x-4=(2x+1)(x-2
We move all terms to the left:
x(2x-4-((2x+1)(x-2)=0
We multiply parentheses ..
x(2x-4-((+2x^2-4x+x-2)=0
| -20=j+75 | | x+(x+2)+(x+4)=50 | | d/9=4 | | |3x+5|=4x-2 | | 10x-10-3x-6=x+2/3 | | 3(2x+4)=12(x+1) | | h+45=94 | | (5x+4)÷(7x+4)=3/4 | | F(x)=-9x^2+6x-1 | | Y7f+17=66 | | z+-40=20 | | 2/17+3/7(3x−5)=−4 | | 7x+5=-4x+8 | | g+-38=-82 | | 12x^2-240x+700=0 | | 16−3p=2/3p+5 | | -17n-16=-16-19n+30 | | w-20=-6 | | 12^xx3^3x=18 | | 99=t+52 | | 2(x+3)=-5x-12 | | 93=3k | | 12x-18+34=10x+26 | | 12^x×3^3x=18 | | c+-8=62 | | 9y–15=-42 | | 1/6x-3=3/2x | | 6=1-1n+5 | | 8x-1+4x=15 | | 1/2x-10=70 | | 6x-7+3x=12 | | -t+2+10t=8t-5 |