x(2x-5)=(2x+4)(x-4)

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Solution for x(2x-5)=(2x+4)(x-4) equation: 



x(2x-5)=(2x+4)(x-4)

We move all terms to the left:

x(2x-5)-((2x+4)(x-4))=0

We multiply parentheses

2x^2-5x-((2x+4)(x-4))=0

We multiply parentheses ..

2x^2-((+2x^2-8x+4x-16))-5x=0



We calculate terms in parentheses: -((+2x^2-8x+4x-16)), so:

(+2x^2-8x+4x-16)

We get rid of parentheses

2x^2-8x+4x-16

We add all the numbers together, and all the variables

2x^2-4x-16

Back to the equation:

-(2x^2-4x-16)



We add all the numbers together, and all the variables

2x^2-5x-(2x^2-4x-16)=0

We get rid of parentheses

2x^2-2x^2-5x+4x+16=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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