x(2x-7)=(2x+6)(x-6)

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Solution for x(2x-7)=(2x+6)(x-6) equation: 



x(2x-7)=(2x+6)(x-6)

We move all terms to the left:

x(2x-7)-((2x+6)(x-6))=0

We multiply parentheses

2x^2-7x-((2x+6)(x-6))=0

We multiply parentheses ..

2x^2-((+2x^2-12x+6x-36))-7x=0



We calculate terms in parentheses: -((+2x^2-12x+6x-36)), so:

(+2x^2-12x+6x-36)

We get rid of parentheses

2x^2-12x+6x-36

We add all the numbers together, and all the variables

2x^2-6x-36

Back to the equation:

-(2x^2-6x-36)



We add all the numbers together, and all the variables

2x^2-7x-(2x^2-6x-36)=0

We get rid of parentheses

2x^2-2x^2-7x+6x+36=0

We add all the numbers together, and all the variables

-1x+36=0

We move all terms containing x to the left, all other terms to the right

-x=-36

x=-36/-1

x=+36

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