x(3+x)=x2+5x-2

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Solution for x(3+x)=x2+5x-2 equation:



x(3+x)=x2+5x-2
We move all terms to the left:
x(3+x)-(x2+5x-2)=0
We add all the numbers together, and all the variables
-(+x^2+5x-2)+x(x+3)=0
We multiply parentheses
-(+x^2+5x-2)+x^2+3x=0
We get rid of parentheses
-x^2+x^2-5x+3x+2=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1

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