x(3-x)=x-(x2-2x+4)

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Solution for x(3-x)=x-(x2-2x+4) equation: 



x(3-x)=x-(x2-2x+4)

We move all terms to the left:

x(3-x)-(x-(x2-2x+4))=0

We add all the numbers together, and all the variables

-(x-(+x^2-2x+4))+x(-1x+3)=0

We multiply parentheses

-(x-(+x^2-2x+4))-1x^2+3x=0



We calculate terms in parentheses: -(x-(+x^2-2x+4)), so:

x-(+x^2-2x+4)

determiningTheFunctionDomain
-(+x^2-2x+4)+x

We get rid of parentheses

-x^2+2x+x-4

We add all the numbers together, and all the variables

-1x^2+3x-4

Back to the equation:

-(-1x^2+3x-4)



We add all the numbers together, and all the variables

-1x^2-(-1x^2+3x-4)+3x=0

We get rid of parentheses

-1x^2+1x^2-3x+3x+4=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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