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x(3/2)=16.2
We move all terms to the left:
x(3/2)-(16.2)=0
We add all the numbers together, and all the variables
x(+3/2)-(16.2)=0
We add all the numbers together, and all the variables
x(+3/2)-16.2=0
We multiply parentheses
3x^2-16.2=0
a = 3; b = 0; c = -16.2;
Δ = b2-4ac
Δ = 02-4·3·(-16.2)
Δ = 194.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{194.4}}{2*3}=\frac{0-\sqrt{194.4}}{6} =-\frac{\sqrt{}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{194.4}}{2*3}=\frac{0+\sqrt{194.4}}{6} =\frac{\sqrt{}}{6} $
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