x(3x+1)=x(5-x)-2

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Solution for x(3x+1)=x(5-x)-2 equation: 



x(3x+1)=x(5-x)-2

We move all terms to the left:

x(3x+1)-(x(5-x)-2)=0

We add all the numbers together, and all the variables

x(3x+1)-(x(-1x+5)-2)=0

We multiply parentheses

3x^2+x-(x(-1x+5)-2)=0



We calculate terms in parentheses: -(x(-1x+5)-2), so:

x(-1x+5)-2

We multiply parentheses

-1x^2+5x-2

Back to the equation:

-(-1x^2+5x-2)



We get rid of parentheses

3x^2+1x^2-5x+x+2=0

We add all the numbers together, and all the variables

4x^2-4x+2=0

a = 4; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·4·2
Δ = -16
Delta is less than zero, so there is no solution for the equation

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