x(3x+13)=2920

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Solution for x(3x+13)=2920 equation:



x(3x+13)=2920
We move all terms to the left:
x(3x+13)-(2920)=0
We multiply parentheses
3x^2+13x-2920=0
a = 3; b = 13; c = -2920;
Δ = b2-4ac
Δ = 132-4·3·(-2920)
Δ = 35209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{35209}}{2*3}=\frac{-13-\sqrt{35209}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{35209}}{2*3}=\frac{-13+\sqrt{35209}}{6} $

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