x(3x+3)=48

Solution for x(3x+3)=48 equation:

x(3x+3)=48

We move all terms to the left:

x(3x+3)-(48)=0

We multiply parentheses

3x^2+3x-48=0

a = 3; b = 3; c = -48;
Δ = b2-4ac
Δ = 32-4·3·(-48)
Δ = 585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{585}=\sqrt{9*65}=\sqrt{9}*\sqrt{65}=3\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{65}}{2*3}=\frac{-3-3\sqrt{65}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{65}}{2*3}=\frac{-3+3\sqrt{65}}{6}
$