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x(3x+40)+4x=360
We move all terms to the left:
x(3x+40)+4x-(360)=0
We add all the numbers together, and all the variables
4x+x(3x+40)-360=0
We multiply parentheses
3x^2+4x+40x-360=0
We add all the numbers together, and all the variables
3x^2+44x-360=0
a = 3; b = 44; c = -360;
Δ = b2-4ac
Δ = 442-4·3·(-360)
Δ = 6256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6256}=\sqrt{16*391}=\sqrt{16}*\sqrt{391}=4\sqrt{391}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{391}}{2*3}=\frac{-44-4\sqrt{391}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{391}}{2*3}=\frac{-44+4\sqrt{391}}{6} $
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