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x(3x+6)=8(x+22)
We move all terms to the left:
x(3x+6)-(8(x+22))=0
We multiply parentheses
3x^2+6x-(8(x+22))=0
We calculate terms in parentheses: -(8(x+22)), so:We get rid of parentheses
8(x+22)
We multiply parentheses
8x+176
Back to the equation:
-(8x+176)
3x^2+6x-8x-176=0
We add all the numbers together, and all the variables
3x^2-2x-176=0
a = 3; b = -2; c = -176;
Δ = b2-4ac
Δ = -22-4·3·(-176)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-46}{2*3}=\frac{-44}{6} =-7+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+46}{2*3}=\frac{48}{6} =8 $
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