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x(3x-1)=94
We move all terms to the left:
x(3x-1)-(94)=0
We multiply parentheses
3x^2-1x-94=0
a = 3; b = -1; c = -94;
Δ = b2-4ac
Δ = -12-4·3·(-94)
Δ = 1129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1129}}{2*3}=\frac{1-\sqrt{1129}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1129}}{2*3}=\frac{1+\sqrt{1129}}{6} $
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