x(3x-2)+x(2x-2)=(5x+4)(x-8)

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Solution for x(3x-2)+x(2x-2)=(5x+4)(x-8) equation: 



x(3x-2)+x(2x-2)=(5x+4)(x-8)

We move all terms to the left:

x(3x-2)+x(2x-2)-((5x+4)(x-8))=0

We multiply parentheses

3x^2+2x^2-2x-2x-((5x+4)(x-8))=0

We multiply parentheses ..

3x^2+2x^2-((+5x^2-40x+4x-32))-2x-2x=0



We calculate terms in parentheses: -((+5x^2-40x+4x-32)), so:

(+5x^2-40x+4x-32)

We get rid of parentheses

5x^2-40x+4x-32

We add all the numbers together, and all the variables

5x^2-36x-32

Back to the equation:

-(5x^2-36x-32)



We add all the numbers together, and all the variables

5x^2-4x-(5x^2-36x-32)=0

We get rid of parentheses

5x^2-5x^2-4x+36x+32=0

We add all the numbers together, and all the variables

32x+32=0

We move all terms containing x to the left, all other terms to the right

32x=-32

x=-32/32

x=-1

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