x(3x-3)=(3x+3)(x-3)

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Solution for x(3x-3)=(3x+3)(x-3) equation: 



x(3x-3)=(3x+3)(x-3)

We move all terms to the left:

x(3x-3)-((3x+3)(x-3))=0

We multiply parentheses

3x^2-3x-((3x+3)(x-3))=0

We multiply parentheses ..

3x^2-((+3x^2-9x+3x-9))-3x=0



We calculate terms in parentheses: -((+3x^2-9x+3x-9)), so:

(+3x^2-9x+3x-9)

We get rid of parentheses

3x^2-9x+3x-9

We add all the numbers together, and all the variables

3x^2-6x-9

Back to the equation:

-(3x^2-6x-9)



We add all the numbers together, and all the variables

3x^2-3x-(3x^2-6x-9)=0

We get rid of parentheses

3x^2-3x^2-3x+6x+9=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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