x(3x-3)=(3x+7)(x-5)

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Solution for x(3x-3)=(3x+7)(x-5) equation: 



x(3x-3)=(3x+7)(x-5)

We move all terms to the left:

x(3x-3)-((3x+7)(x-5))=0

We multiply parentheses

3x^2-3x-((3x+7)(x-5))=0

We multiply parentheses ..

3x^2-((+3x^2-15x+7x-35))-3x=0



We calculate terms in parentheses: -((+3x^2-15x+7x-35)), so:

(+3x^2-15x+7x-35)

We get rid of parentheses

3x^2-15x+7x-35

We add all the numbers together, and all the variables

3x^2-8x-35

Back to the equation:

-(3x^2-8x-35)



We add all the numbers together, and all the variables

3x^2-3x-(3x^2-8x-35)=0

We get rid of parentheses

3x^2-3x^2-3x+8x+35=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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