If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(3x-3)=136
We move all terms to the left:
x(3x-3)-(136)=0
We multiply parentheses
3x^2-3x-136=0
a = 3; b = -3; c = -136;
Δ = b2-4ac
Δ = -32-4·3·(-136)
Δ = 1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1641}}{2*3}=\frac{3-\sqrt{1641}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1641}}{2*3}=\frac{3+\sqrt{1641}}{6} $
| 35y+8=35 | | 2(5v+6)=-18-4v | | 3n-9=5+3n | | Y=0.4x+6.6 | | 3(4n+3)-2=12n+7 | | 1/2X^2-3x-7/2=0 | | 1/2X^2-3x-7÷2=0 | | 24x+12=8(x+6) | | (2)/(5)x+4=(7)/(10)x-8 | | 2/3y+1/6=-3/4y+1 | | 3x+1+4x+4=90 | | 2/5+4=7/10x-8 | | 24x-12=24 | | -2n+4=-3n+9 | | 2(x-1)^-4=52 | | 5=3-0.5x | | 2(n+3)-n=-n-4(n+2) | | 9(x+3)+x=3(x-7)-8 | | 3^x+2-3^x-2=80 | | 7.4x-2.3=19.9 | | 5^-x+1+5^1+x=26 | | 579.10=500(1+0.29)(1+x)(1+0.03) | | 11x+9x=-4 | | 6(2+y)=3(3-1y) | | 180(n-2)=126n | | -2(t-5)-(t+9)=4 | | 6h+13-5=0 | | 6h2+13h-5=0 | | 4(7+y)=2(7-y)+2 | | 3m-9=5+3m | | 2x×x=512 | | 3(4m+3)-2=12m+7 |