x(3x-5)=(3x+8)(x-7)

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Solution for x(3x-5)=(3x+8)(x-7) equation: 



x(3x-5)=(3x+8)(x-7)

We move all terms to the left:

x(3x-5)-((3x+8)(x-7))=0

We multiply parentheses

3x^2-5x-((3x+8)(x-7))=0

We multiply parentheses ..

3x^2-((+3x^2-21x+8x-56))-5x=0



We calculate terms in parentheses: -((+3x^2-21x+8x-56)), so:

(+3x^2-21x+8x-56)

We get rid of parentheses

3x^2-21x+8x-56

We add all the numbers together, and all the variables

3x^2-13x-56

Back to the equation:

-(3x^2-13x-56)



We add all the numbers together, and all the variables

3x^2-5x-(3x^2-13x-56)=0

We get rid of parentheses

3x^2-3x^2-5x+13x+56=0

We add all the numbers together, and all the variables

8x+56=0

We move all terms containing x to the left, all other terms to the right

8x=-56

x=-56/8

x=-7

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