x(3x-6)=(3x+4)(x-2)

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Solution for x(3x-6)=(3x+4)(x-2) equation: 



x(3x-6)=(3x+4)(x-2)

We move all terms to the left:

x(3x-6)-((3x+4)(x-2))=0

We multiply parentheses

3x^2-6x-((3x+4)(x-2))=0

We multiply parentheses ..

3x^2-((+3x^2-6x+4x-8))-6x=0



We calculate terms in parentheses: -((+3x^2-6x+4x-8)), so:

(+3x^2-6x+4x-8)

We get rid of parentheses

3x^2-6x+4x-8

We add all the numbers together, and all the variables

3x^2-2x-8

Back to the equation:

-(3x^2-2x-8)



We add all the numbers together, and all the variables

3x^2-6x-(3x^2-2x-8)=0

We get rid of parentheses

3x^2-3x^2-6x+2x+8=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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