x(3x-7)=(3x+8)(x-6)

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Solution for x(3x-7)=(3x+8)(x-6) equation: 



x(3x-7)=(3x+8)(x-6)

We move all terms to the left:

x(3x-7)-((3x+8)(x-6))=0

We multiply parentheses

3x^2-7x-((3x+8)(x-6))=0

We multiply parentheses ..

3x^2-((+3x^2-18x+8x-48))-7x=0



We calculate terms in parentheses: -((+3x^2-18x+8x-48)), so:

(+3x^2-18x+8x-48)

We get rid of parentheses

3x^2-18x+8x-48

We add all the numbers together, and all the variables

3x^2-10x-48

Back to the equation:

-(3x^2-10x-48)



We add all the numbers together, and all the variables

3x^2-7x-(3x^2-10x-48)=0

We get rid of parentheses

3x^2-3x^2-7x+10x+48=0

We add all the numbers together, and all the variables

3x+48=0

We move all terms containing x to the left, all other terms to the right

3x=-48

x=-48/3

x=-16

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