x(3x-8)=(3x+2)(x-3)

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Solution for x(3x-8)=(3x+2)(x-3) equation: 



x(3x-8)=(3x+2)(x-3)

We move all terms to the left:

x(3x-8)-((3x+2)(x-3))=0

We multiply parentheses

3x^2-8x-((3x+2)(x-3))=0

We multiply parentheses ..

3x^2-((+3x^2-9x+2x-6))-8x=0



We calculate terms in parentheses: -((+3x^2-9x+2x-6)), so:

(+3x^2-9x+2x-6)

We get rid of parentheses

3x^2-9x+2x-6

We add all the numbers together, and all the variables

3x^2-7x-6

Back to the equation:

-(3x^2-7x-6)



We add all the numbers together, and all the variables

3x^2-8x-(3x^2-7x-6)=0

We get rid of parentheses

3x^2-3x^2-8x+7x+6=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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