x(3x-9)=(3x+6)(x-7)

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Solution for x(3x-9)=(3x+6)(x-7) equation: 



x(3x-9)=(3x+6)(x-7)

We move all terms to the left:

x(3x-9)-((3x+6)(x-7))=0

We multiply parentheses

3x^2-9x-((3x+6)(x-7))=0

We multiply parentheses ..

3x^2-((+3x^2-21x+6x-42))-9x=0



We calculate terms in parentheses: -((+3x^2-21x+6x-42)), so:

(+3x^2-21x+6x-42)

We get rid of parentheses

3x^2-21x+6x-42

We add all the numbers together, and all the variables

3x^2-15x-42

Back to the equation:

-(3x^2-15x-42)



We add all the numbers together, and all the variables

3x^2-9x-(3x^2-15x-42)=0

We get rid of parentheses

3x^2-3x^2-9x+15x+42=0

We add all the numbers together, and all the variables

6x+42=0

We move all terms containing x to the left, all other terms to the right

6x=-42

x=-42/6

x=-7

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