x(3y+x)+(2y+1)(y-2)=

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Solution for x(3y+x)+(2y+1)(y-2)= equation: 


Simplifying
x(3y + x) + (2y + 1)(y + -2) = 0

Reorder the terms:
x(x + 3y) + (2y + 1)(y + -2) = 0
(x * x + 3y * x) + (2y + 1)(y + -2) = 0

Reorder the terms:
(3xy + x2) + (2y + 1)(y + -2) = 0
(3xy + x2) + (2y + 1)(y + -2) = 0

Reorder the terms:
3xy + x2 + (1 + 2y)(y + -2) = 0

Reorder the terms:
3xy + x2 + (1 + 2y)(-2 + y) = 0

Multiply (1 + 2y) * (-2 + y)
3xy + x2 + (1(-2 + y) + 2y * (-2 + y)) = 0
3xy + x2 + ((-2 * 1 + y * 1) + 2y * (-2 + y)) = 0
3xy + x2 + ((-2 + 1y) + 2y * (-2 + y)) = 0
3xy + x2 + (-2 + 1y + (-2 * 2y + y * 2y)) = 0
3xy + x2 + (-2 + 1y + (-4y + 2y2)) = 0

Combine like terms: 1y + -4y = -3y
3xy + x2 + (-2 + -3y + 2y2) = 0

Reorder the terms:
-2 + 3xy + x2 + -3y + 2y2 = 0

Solving
-2 + 3xy + x2 + -3y + 2y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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