x(4-2x)=2(2x-16)

Solution for x(4-2x)=2(2x-16) equation:

x(4-2x)=2(2x-16)

We move all terms to the left:

x(4-2x)-(2(2x-16))=0

We add all the numbers together, and all the variables

x(-2x+4)-(2(2x-16))=0

We multiply parentheses

-2x^2+4x-(2(2x-16))=0


We calculate terms in parentheses: -(2(2x-16)), so:

2(2x-16)

We multiply parentheses

4x-32

Back to the equation:

-(4x-32)


We get rid of parentheses

-2x^2+4x-4x+32=0

We add all the numbers together, and all the variables

-2x^2+32=0

a = -2; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-2)·32
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-2}=\frac{-16}{-4}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-2}=\frac{16}{-4}
=-4
$