x(4x+15)+4=0

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Solution for x(4x+15)+4=0 equation:



x(4x+15)+4=0
We multiply parentheses
4x^2+15x+4=0
a = 4; b = 15; c = +4;
Δ = b2-4ac
Δ = 152-4·4·4
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{161}}{2*4}=\frac{-15-\sqrt{161}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{161}}{2*4}=\frac{-15+\sqrt{161}}{8} $

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