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x(4x+6)=70
We move all terms to the left:
x(4x+6)-(70)=0
We multiply parentheses
4x^2+6x-70=0
a = 4; b = 6; c = -70;
Δ = b2-4ac
Δ = 62-4·4·(-70)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-34}{2*4}=\frac{-40}{8} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+34}{2*4}=\frac{28}{8} =3+1/2 $
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