x(4x-3)=(4x+9)(x-4)

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Solution for x(4x-3)=(4x+9)(x-4) equation: 



x(4x-3)=(4x+9)(x-4)

We move all terms to the left:

x(4x-3)-((4x+9)(x-4))=0

We multiply parentheses

4x^2-3x-((4x+9)(x-4))=0

We multiply parentheses ..

4x^2-((+4x^2-16x+9x-36))-3x=0



We calculate terms in parentheses: -((+4x^2-16x+9x-36)), so:

(+4x^2-16x+9x-36)

We get rid of parentheses

4x^2-16x+9x-36

We add all the numbers together, and all the variables

4x^2-7x-36

Back to the equation:

-(4x^2-7x-36)



We add all the numbers together, and all the variables

4x^2-3x-(4x^2-7x-36)=0

We get rid of parentheses

4x^2-4x^2-3x+7x+36=0

We add all the numbers together, and all the variables

4x+36=0

We move all terms containing x to the left, all other terms to the right

4x=-36

x=-36/4

x=-9

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