x(4x-4)=(4x+1)(x-1)

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Solution for x(4x-4)=(4x+1)(x-1) equation: 



x(4x-4)=(4x+1)(x-1)

We move all terms to the left:

x(4x-4)-((4x+1)(x-1))=0

We multiply parentheses

4x^2-4x-((4x+1)(x-1))=0

We multiply parentheses ..

4x^2-((+4x^2-4x+x-1))-4x=0



We calculate terms in parentheses: -((+4x^2-4x+x-1)), so:

(+4x^2-4x+x-1)

We get rid of parentheses

4x^2-4x+x-1

We add all the numbers together, and all the variables

4x^2-3x-1

Back to the equation:

-(4x^2-3x-1)



We add all the numbers together, and all the variables

4x^2-4x-(4x^2-3x-1)=0

We get rid of parentheses

4x^2-4x^2-4x+3x+1=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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