x(4x-4)=(4x+6)(x-1)

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Solution for x(4x-4)=(4x+6)(x-1) equation: 



x(4x-4)=(4x+6)(x-1)

We move all terms to the left:

x(4x-4)-((4x+6)(x-1))=0

We multiply parentheses

4x^2-4x-((4x+6)(x-1))=0

We multiply parentheses ..

4x^2-((+4x^2-4x+6x-6))-4x=0



We calculate terms in parentheses: -((+4x^2-4x+6x-6)), so:

(+4x^2-4x+6x-6)

We get rid of parentheses

4x^2-4x+6x-6

We add all the numbers together, and all the variables

4x^2+2x-6

Back to the equation:

-(4x^2+2x-6)



We add all the numbers together, and all the variables

4x^2-4x-(4x^2+2x-6)=0

We get rid of parentheses

4x^2-4x^2-4x-2x+6=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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