x(4x-8)=(4x+7)(x-5)

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Solution for x(4x-8)=(4x+7)(x-5) equation: 



x(4x-8)=(4x+7)(x-5)

We move all terms to the left:

x(4x-8)-((4x+7)(x-5))=0

We multiply parentheses

4x^2-8x-((4x+7)(x-5))=0

We multiply parentheses ..

4x^2-((+4x^2-20x+7x-35))-8x=0



We calculate terms in parentheses: -((+4x^2-20x+7x-35)), so:

(+4x^2-20x+7x-35)

We get rid of parentheses

4x^2-20x+7x-35

We add all the numbers together, and all the variables

4x^2-13x-35

Back to the equation:

-(4x^2-13x-35)



We add all the numbers together, and all the variables

4x^2-8x-(4x^2-13x-35)=0

We get rid of parentheses

4x^2-4x^2-8x+13x+35=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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