x(4x-8)=(4x+7)(x-9)

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Solution for x(4x-8)=(4x+7)(x-9) equation: 



x(4x-8)=(4x+7)(x-9)

We move all terms to the left:

x(4x-8)-((4x+7)(x-9))=0

We multiply parentheses

4x^2-8x-((4x+7)(x-9))=0

We multiply parentheses ..

4x^2-((+4x^2-36x+7x-63))-8x=0



We calculate terms in parentheses: -((+4x^2-36x+7x-63)), so:

(+4x^2-36x+7x-63)

We get rid of parentheses

4x^2-36x+7x-63

We add all the numbers together, and all the variables

4x^2-29x-63

Back to the equation:

-(4x^2-29x-63)



We add all the numbers together, and all the variables

4x^2-8x-(4x^2-29x-63)=0

We get rid of parentheses

4x^2-4x^2-8x+29x+63=0

We add all the numbers together, and all the variables

21x+63=0

We move all terms containing x to the left, all other terms to the right

21x=-63

x=-63/21

x=-3

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