x(5-x)=2(x+3)

Solution for x(5-x)=2(x+3) equation:

x(5-x)=2(x+3)

We move all terms to the left:

x(5-x)-(2(x+3))=0

We add all the numbers together, and all the variables

x(-1x+5)-(2(x+3))=0

We multiply parentheses

-1x^2+5x-(2(x+3))=0


We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)


We get rid of parentheses

-1x^2+5x-2x-6=0

We add all the numbers together, and all the variables

-1x^2+3x-6=0

a = -1; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-1)·(-6)
Δ = -15
Delta is less than zero, so there is no solution for the equation