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x(5x+8)=13
We move all terms to the left:
x(5x+8)-(13)=0
We multiply parentheses
5x^2+8x-13=0
a = 5; b = 8; c = -13;
Δ = b2-4ac
Δ = 82-4·5·(-13)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-18}{2*5}=\frac{-26}{10} =-2+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+18}{2*5}=\frac{10}{10} =1 $
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