x(5x-2)=(5x+4)(x-1)

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Solution for x(5x-2)=(5x+4)(x-1) equation: 



x(5x-2)=(5x+4)(x-1)

We move all terms to the left:

x(5x-2)-((5x+4)(x-1))=0

We multiply parentheses

5x^2-2x-((5x+4)(x-1))=0

We multiply parentheses ..

5x^2-((+5x^2-5x+4x-4))-2x=0



We calculate terms in parentheses: -((+5x^2-5x+4x-4)), so:

(+5x^2-5x+4x-4)

We get rid of parentheses

5x^2-5x+4x-4

We add all the numbers together, and all the variables

5x^2-1x-4

Back to the equation:

-(5x^2-1x-4)



We add all the numbers together, and all the variables

5x^2-2x-(5x^2-1x-4)=0

We get rid of parentheses

5x^2-5x^2-2x+1x+4=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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