x(5x-7)=(5x+2)(x-3)

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Solution for x(5x-7)=(5x+2)(x-3) equation: 



x(5x-7)=(5x+2)(x-3)

We move all terms to the left:

x(5x-7)-((5x+2)(x-3))=0

We multiply parentheses

5x^2-7x-((5x+2)(x-3))=0

We multiply parentheses ..

5x^2-((+5x^2-15x+2x-6))-7x=0



We calculate terms in parentheses: -((+5x^2-15x+2x-6)), so:

(+5x^2-15x+2x-6)

We get rid of parentheses

5x^2-15x+2x-6

We add all the numbers together, and all the variables

5x^2-13x-6

Back to the equation:

-(5x^2-13x-6)



We add all the numbers together, and all the variables

5x^2-7x-(5x^2-13x-6)=0

We get rid of parentheses

5x^2-5x^2-7x+13x+6=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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