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x(5x-9)=(5x+9)(x-4)
We move all terms to the left:
x(5x-9)-((5x+9)(x-4))=0
We multiply parentheses
5x^2-9x-((5x+9)(x-4))=0
We multiply parentheses ..
5x^2-((+5x^2-20x+9x-36))-9x=0
We calculate terms in parentheses: -((+5x^2-20x+9x-36)), so:We add all the numbers together, and all the variables
(+5x^2-20x+9x-36)
We get rid of parentheses
5x^2-20x+9x-36
We add all the numbers together, and all the variables
5x^2-11x-36
Back to the equation:
-(5x^2-11x-36)
5x^2-9x-(5x^2-11x-36)=0
We get rid of parentheses
5x^2-5x^2-9x+11x+36=0
We add all the numbers together, and all the variables
2x+36=0
We move all terms containing x to the left, all other terms to the right
2x=-36
x=-36/2
x=-18
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