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x(6x-7)=3288
We move all terms to the left:
x(6x-7)-(3288)=0
We multiply parentheses
6x^2-7x-3288=0
a = 6; b = -7; c = -3288;
Δ = b2-4ac
Δ = -72-4·6·(-3288)
Δ = 78961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{78961}=281$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-281}{2*6}=\frac{-274}{12} =-22+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+281}{2*6}=\frac{288}{12} =24 $
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