x(7-6x)=(1-3x)(1+2x)

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Solution for x(7-6x)=(1-3x)(1+2x) equation: 



x(7-6x)=(1-3x)(1+2x)

We move all terms to the left:

x(7-6x)-((1-3x)(1+2x))=0

We add all the numbers together, and all the variables

x(-6x+7)-((-3x+1)(2x+1))=0

We multiply parentheses

-6x^2+7x-((-3x+1)(2x+1))=0

We multiply parentheses ..

-6x^2-((-6x^2-3x+2x+1))+7x=0



We calculate terms in parentheses: -((-6x^2-3x+2x+1)), so:

(-6x^2-3x+2x+1)

We get rid of parentheses

-6x^2-3x+2x+1

We add all the numbers together, and all the variables

-6x^2-1x+1

Back to the equation:

-(-6x^2-1x+1)



We get rid of parentheses

-6x^2+6x^2+1x+7x-1=0

We add all the numbers together, and all the variables

8x-1=0

We move all terms containing x to the left, all other terms to the right

8x=1

x=1/8

x=1/8

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