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x(8x-5)=50
We move all terms to the left:
x(8x-5)-(50)=0
We multiply parentheses
8x^2-5x-50=0
a = 8; b = -5; c = -50;
Δ = b2-4ac
Δ = -52-4·8·(-50)
Δ = 1625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1625}=\sqrt{25*65}=\sqrt{25}*\sqrt{65}=5\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{65}}{2*8}=\frac{5-5\sqrt{65}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{65}}{2*8}=\frac{5+5\sqrt{65}}{16} $
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