x(9x-10)=(3x-2)(3x-2)

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Solution for x(9x-10)=(3x-2)(3x-2) equation: 



x(9x-10)=(3x-2)(3x-2)

We move all terms to the left:

x(9x-10)-((3x-2)(3x-2))=0

We multiply parentheses

9x^2-10x-((3x-2)(3x-2))=0

We multiply parentheses ..

9x^2-((+9x^2-6x-6x+4))-10x=0



We calculate terms in parentheses: -((+9x^2-6x-6x+4)), so:

(+9x^2-6x-6x+4)

We get rid of parentheses

9x^2-6x-6x+4

We add all the numbers together, and all the variables

9x^2-12x+4

Back to the equation:

-(9x^2-12x+4)



We add all the numbers together, and all the variables

9x^2-10x-(9x^2-12x+4)=0

We get rid of parentheses

9x^2-9x^2-10x+12x-4=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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