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x(9x-27)=972
We move all terms to the left:
x(9x-27)-(972)=0
We multiply parentheses
9x^2-27x-972=0
a = 9; b = -27; c = -972;
Δ = b2-4ac
Δ = -272-4·9·(-972)
Δ = 35721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{35721}=189$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-189}{2*9}=\frac{-162}{18} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+189}{2*9}=\frac{216}{18} =12 $
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