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x(9x-8)=(9x+2)(x-1)
We move all terms to the left:
x(9x-8)-((9x+2)(x-1))=0
We multiply parentheses
9x^2-8x-((9x+2)(x-1))=0
We multiply parentheses ..
9x^2-((+9x^2-9x+2x-2))-8x=0
We calculate terms in parentheses: -((+9x^2-9x+2x-2)), so:We add all the numbers together, and all the variables
(+9x^2-9x+2x-2)
We get rid of parentheses
9x^2-9x+2x-2
We add all the numbers together, and all the variables
9x^2-7x-2
Back to the equation:
-(9x^2-7x-2)
9x^2-8x-(9x^2-7x-2)=0
We get rid of parentheses
9x^2-9x^2-8x+7x+2=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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