x(f(x)+f(-x)+2)+2f(-x)=0

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Solution for x(f(x)+f(-x)+2)+2f(-x)=0 equation:


Simplifying
x(f(x) + f(-1x) + 2) + 2f(-1x) = 0

Multiply f * x
x(fx + f(-1x) + 2) + 2f(-1x) = 0

Remove parenthesis around (-1x)
x(fx + f * -1x + 2) + 2f(-1x) = 0

Reorder the terms for easier multiplication:
x(fx + -1f * x + 2) + 2f(-1x) = 0

Multiply f * x
x(fx + -1fx + 2) + 2f(-1x) = 0

Reorder the terms:
x(2 + fx + -1fx) + 2f(-1x) = 0

Combine like terms: fx + -1fx = 0
x(2 + 0) + 2f(-1x) = 0
x(2) + 2f(-1x) = 0

Reorder the terms for easier multiplication:
2x + 2f(-1x) = 0

Remove parenthesis around (-1x)
2x + 2f * -1x = 0

Reorder the terms for easier multiplication:
2x + 2 * -1f * x = 0

Multiply 2 * -1
2x + -2f * x = 0

Multiply f * x
2x + -2fx = 0

Reorder the terms:
-2fx + 2x = 0

Solving
-2fx + 2x = 0

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-2x' to each side of the equation.
-2fx + 2x + -2x = 0 + -2x

Combine like terms: 2x + -2x = 0
-2fx + 0 = 0 + -2x
-2fx = 0 + -2x
Remove the zero:
-2fx = -2x

Divide each side by '-2x'.
f = 1

Simplifying
f = 1

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