x(x+-2)=(x-4)2

Solution for x(x+-2)=(x-4)2 equation:

x(x+-2)=(x-4)2

We move all terms to the left:

x(x+-2)-((x-4)2)=0

We add all the numbers together, and all the variables

x(x-2)-((x-4)2)=0

We multiply parentheses

x^2-2x-((x-4)2)=0


We calculate terms in parentheses: -((x-4)2), so:

(x-4)2

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)


We get rid of parentheses

x^2-2x-2x+8=0

We add all the numbers together, and all the variables

x^2-4x+8=0

a = 1; b = -4; c = +8;
Δ = b2-4ac
Δ = -42-4·1·8
Δ = -16
Delta is less than zero, so there is no solution for the equation