x(x+1)(x+2)(x+3)=15

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Solution for x(x+1)(x+2)(x+3)=15 equation: 



x(x+1)(x+2)(x+3)=15

We move all terms to the left:

x(x+1)(x+2)(x+3)-(15)=0

We multiply parentheses ..

x(+x^2+2x+x+2)(x+3)-15=0

We move all terms containing x to the left, all other terms to the right

x(+x^2+2x+x+2)(x+3)=15

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