x(x+1)(x+2)=320

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Solution for x(x+1)(x+2)=320 equation: 


Simplifying
x(x + 1)(x + 2) = 320

Reorder the terms:
x(1 + x)(x + 2) = 320

Reorder the terms:
x(1 + x)(2 + x) = 320

Multiply (1 + x) * (2 + x)
x(1(2 + x) + x(2 + x)) = 320
x((2 * 1 + x * 1) + x(2 + x)) = 320
x((2 + 1x) + x(2 + x)) = 320
x(2 + 1x + (2 * x + x * x)) = 320
x(2 + 1x + (2x + x2)) = 320

Combine like terms: 1x + 2x = 3x
x(2 + 3x + x2) = 320
(2 * x + 3x * x + x2 * x) = 320
(2x + 3x2 + x3) = 320

Solving
2x + 3x2 + x3 = 320

Solving for variable 'x'.

Reorder the terms:
-320 + 2x + 3x2 + x3 = 320 + -320

Combine like terms: 320 + -320 = 0
-320 + 2x + 3x2 + x3 = 0

The solution to this equation could not be determined.

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