x(x+1)(x-1)(x+2)+1=0

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Solution for x(x+1)(x-1)(x+2)+1=0 equation: 


Simplifying
x(x + 1)(x + -1)(x + 2) + 1 = 0

Reorder the terms:
x(1 + x)(x + -1)(x + 2) + 1 = 0

Reorder the terms:
x(1 + x)(-1 + x)(x + 2) + 1 = 0

Reorder the terms:
x(1 + x)(-1 + x)(2 + x) + 1 = 0

Multiply (1 + x) * (-1 + x)
x(1(-1 + x) + x(-1 + x))(2 + x) + 1 = 0
x((-1 * 1 + x * 1) + x(-1 + x))(2 + x) + 1 = 0
x((-1 + 1x) + x(-1 + x))(2 + x) + 1 = 0
x(-1 + 1x + (-1 * x + x * x))(2 + x) + 1 = 0
x(-1 + 1x + (-1x + x2))(2 + x) + 1 = 0

Combine like terms: 1x + -1x = 0
x(-1 + 0 + x2)(2 + x) + 1 = 0
x(-1 + x2)(2 + x) + 1 = 0

Multiply (-1 + x2) * (2 + x)
x(-1(2 + x) + x2(2 + x)) + 1 = 0
x((2 * -1 + x * -1) + x2(2 + x)) + 1 = 0
x((-2 + -1x) + x2(2 + x)) + 1 = 0
x(-2 + -1x + (2 * x2 + x * x2)) + 1 = 0
x(-2 + -1x + (2x2 + x3)) + 1 = 0
x(-2 + -1x + 2x2 + x3) + 1 = 0
(-2 * x + -1x * x + 2x2 * x + x3 * x) + 1 = 0
(-2x + -1x2 + 2x3 + x4) + 1 = 0

Reorder the terms:
1 + -2x + -1x2 + 2x3 + x4 = 0

Solving
1 + -2x + -1x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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