x(x+1)(x-4)+4(x+1)=0

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Solution for x(x+1)(x-4)+4(x+1)=0 equation: 


Simplifying
x(x + 1)(x + -4) + 4(x + 1) = 0

Reorder the terms:
x(1 + x)(x + -4) + 4(x + 1) = 0

Reorder the terms:
x(1 + x)(-4 + x) + 4(x + 1) = 0

Multiply (1 + x) * (-4 + x)
x(1(-4 + x) + x(-4 + x)) + 4(x + 1) = 0
x((-4 * 1 + x * 1) + x(-4 + x)) + 4(x + 1) = 0
x((-4 + 1x) + x(-4 + x)) + 4(x + 1) = 0
x(-4 + 1x + (-4 * x + x * x)) + 4(x + 1) = 0
x(-4 + 1x + (-4x + x2)) + 4(x + 1) = 0

Combine like terms: 1x + -4x = -3x
x(-4 + -3x + x2) + 4(x + 1) = 0
(-4 * x + -3x * x + x2 * x) + 4(x + 1) = 0
(-4x + -3x2 + x3) + 4(x + 1) = 0

Reorder the terms:
-4x + -3x2 + x3 + 4(1 + x) = 0
-4x + -3x2 + x3 + (1 * 4 + x * 4) = 0
-4x + -3x2 + x3 + (4 + 4x) = 0

Reorder the terms:
4 + -4x + 4x + -3x2 + x3 = 0

Combine like terms: -4x + 4x = 0
4 + 0 + -3x2 + x3 = 0
4 + -3x2 + x3 = 0

Solving
4 + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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